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diffKeys
方法和另外一個(gè)集合或 PHP 數(shù)組的鍵(keys)進(jìn)行比較,然后返回原集合中存在而指定集合中不存在鍵所對(duì)應(yīng)的鍵 / 值對(duì):
$collection = collect([
'one' => 10,
'two' => 20,
'three' => 30,
'four' => 40,
'five' => 50,
]);
$diff = $collection->diffKeys([
'two' => 2,
'four' => 4,
'six' => 6,
'eight' => 8,
]);
$diff->all();
// ['one' => 10, 'three' => 30, 'five' => 50]
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